Question

\(\frac{2}{3}+\frac{5}{7}+\frac{-2}{3}\)

Answer 1

\(\dfrac{2}{3}+\dfrac{5}{7}+\dfrac{-2}{3}=\left(\dfrac{2}{3}-\dfrac{2}{3}\right)+\dfrac{5}{7}=0+\dfrac{5}{7}=\dfrac{5}{7}\)

Answer 2

\(\dfrac{2}{3}+\dfrac{5}{7}+\dfrac{-2}{3}=\dfrac{29}{21}+\dfrac{-2}{3}=\dfrac{5}{7}\)