Question

\(\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{96}+\frac{2}{192}\)

Answer 1

Ta thấy tất cả các phân số đều có mẫu chung là 192

=> \(\frac{128+64+32+16+8+4+2}{192}\)

= \(\frac{254}{192}\)= \(\frac{127}{96}\)

Answer 2

2/3+2/6+2/12+2/24+2/48+2/96+2/192

=2/3+1/3+1/6+1/12+1/24+1/48+1/96

=127/96

Answer 3

\(\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{29}{96}+\frac{2}{192}\)

\(=\frac{2}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}\)

\(=\frac{254}{192}=\frac{127}{96}\)

Answer 4

\(\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{96}+\frac{2}{192}\)

\(=\frac{128+64+32+16+8+4+2}{192}\)

\(=\frac{254}{192}\)

\(=\frac{127}{96}\)