\(\frac{2016+x}{x}+\frac{2520+x}{x}+\frac{3024+x}{x}=\frac{2016}{x}+\frac{x}{x}+\frac{2520}{x}+\frac{x}{x}+\frac{3024}{x}+\frac{x}{x}\)
\(=\frac{2016+2520+3024}{x}+3\)
\(=\frac{7560}{x}+3\)
\(\frac{7560}{x}+3=2523\)
\(\frac{7560}{x}=2520\)
\(x=\frac{7560}{2520}\)
\(x=3\)
Tìm x \(\frac{2016+x}{x}+\frac{2520+x}{x}+\frac{3024+x}{x}=2523\)
Tìm x biết \(\frac{2016+x}{x}+\frac{2520+x}{x}+\frac{3024+x}{x}=2523\)
tìm x , biết :
\(\frac{x-2019}{2018}+\frac{x-2018}{2017}=\frac{x-2017}{2016}+\frac{x-2016}{2015}\)
Tìm x thỏa mãn \(\frac{x}{2016}+\frac{x+1}{2017}=\frac{x+2}{2018}\)\(+\frac{x+3}{2019}\)
Dễ thấy bài này kết quả bằng 2016 rồi nhưng mình cần cách giải
Ai nhanh và đúng sẽ nhận tích nhe !
Tìm số tự nhiên x thỏa mãn:
\(\frac{1}{2016-x}+\frac{1}{2017-x}+\frac{1}{2018-x}=\frac{13}{12}\)
\(\left(1+\frac{2}{1}\right)x\left(1+\frac{2}{2}\right)x\left(1+\frac{2}{3}\right)x\left(1+\frac{2}{4}\right)x...x\left(1+\frac{2}{2016}\right)x\left(1+\frac{2}{2017}\right)\)
tinh bieu thuc tren
1 x \(\frac{1}{15}\) x 1\(\frac{1}{16}\) x 1\(\frac{1}{17}\) x............x 1\(\frac{1}{2016}\) x 1\(\frac{1}{2017}\)
5 Tìm x, biết :(x\(\in\)N)
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{10}+..+\frac{2}{x\left(x+1\right)}=\)\(\frac{2015}{2016}\)
\(A=\left(6:\frac{3}{5}-1\frac{1}{6}x\frac{6}{7}\right):\left(4\frac{1}{5}x\frac{10}{11}+5\frac{2}{11}\right)\)\(B=\left(1-\frac{1}{2}\right)x\left(1-\frac{1}{4}\right)x.......x\left(1-\frac{1}{2015}\right)x\left(1-\frac{1}{2016}\right)\)
\(C=5\frac{9}{10}:\frac{3}{2}-\left(2\frac{1}{3}x4\frac{1}{2}-2x2\frac{1}{3}\right):\frac{7}{4}\)