Question

\(\frac{201-X}{99}+\frac{203-X}{97}\)bằng \(\frac{205-X}{95}+3\)

Answer 1

\(\frac{201-x}{99}+\frac{203-x}{97}=\frac{205-x}{95}+3\)

\(\Leftrightarrow\frac{201-x}{99}+1+\frac{203-x}{97}+1-\frac{205-x}{95}-1=4\)

\(\Leftrightarrow\frac{200-x}{99}+\frac{200-x}{97}-\frac{200-x}{95}=4\)

\(\Leftrightarrow\left(200-x\right)\left(\frac{1}{99}+\frac{1}{97}-\frac{1}{95}\right)=4\)

Bạn tự làm tiếp.

Answer 2

X = -104,695575 

   Đáp số ra lẻ quá bạn nhỉ 

Answer 3

201-x/99+203-x/97=205-x/95+3

201-x/99+1 +203-x/97+1-205-x/95+1=4

200-x/99+200-x/97+200-x/95=4

(200-x)(1/99+1/97+1/95)=4