\(\frac{17}{2}\)x \(\frac{3}{5}\)+ \(\frac{1}{2}\) x \(\frac{3}{5}\)+ \(\frac{3}{5}\)
= \(\frac{51}{10}\)+ \(\frac{3}{10}\)+ \(\frac{3}{5}\)
= \(\frac{27}{5}\)+ \(\frac{3}{5}\)
= \(6\)
bọn bay học ngu còn lâu ông mới nhắc
\(=\frac{3}{5}\cdot\left(\frac{17}{2}+\frac{1}{2}+1\right)=\frac{3}{5}\cdot10=\frac{3}{2}\)
\(\frac{17}{2}x\frac{3}{5}+\frac{1}{2}x\frac{3}{5}+\frac{3}{5}\)
= \(\left(\frac{17}{2}+\frac{1}{2}+1\right)\)x \(\frac{3}{5}\)
= \(10x\frac{3}{5}=6\)
\(\frac{17}{2}\cdot\frac{3}{5}+\frac{1}{2}\cdot\frac{3}{5}+\frac{3}{5}=\frac{3}{5}\cdot\left(\frac{17}{2}+\frac{1}{2}+1\right)\)
\(=\frac{3}{5}\cdot\left(9+1\right)=\frac{3}{5}\cdot10=\frac{30}{5}=6\)
17/2 * 3/5 + 1/2 * 3/5 + 3/5
= ( 17/2 + 1/2 + 1 ) * 3/5
= 10 * 3/5
= 6