Question

\(\frac{1}{4}+\frac{8}{9}\le\frac{x}{36}< 1-\frac{3}{8}+\frac{5}{6}\)   

tìm x ; x e Z

Answer 1

C =22−3 x 4− x =12−3 x +104− x =3(4− x )4− x +104− x =3+104− x ... +199.100 ). x =201251 +201252 +. .... =12√3 (4+2√3√3+1+4−2√3√3−1 )=12√3 .4√3−4+6−2√3+4√3+4−6−2√3(√3−1)(√3+1).

Answer 2

\(\frac{1}{4}+\frac{8}{9}< \frac{x}{36}< 1-\frac{3}{8}+\frac{5}{6}\)

\(=\frac{41}{36}< \frac{x}{36}< \frac{35}{24}\)

=>\(x=35< x< 41\)