Question

\(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{^{6x}}\)

              Tìm x,y 

Answer 1

1+2y/18 = 1+4y/24

=> 24.(1+2y) = 18.(1+4y)

=> 24+48y = 18+72y

=> 24-18 = 72y-48y

=> 6 = 24y

=> y = 1/4

Lại có : 1+6y/6x = 1+4y/24

=> (1+6.1/4) : 6x = (1+4.1/4) : 24

=> 5/12x = 1/12

=> 12x = 5 : 1/12 = 60

=> x = 60 : 5 = 12

Vậy .........

Tk mk nha

Answer 2

Áp dụng t/c dãy tỉ số = nhau, ta có:

1 + 2y/18 = 1 + 6y/6x = 1 + 2y + 1 + 6y/18 + 6x = 2 + 8y/18 + 6x = 2.(1 + 4y)/2.(9 + 3x) = 1 + 4y/9/3x

=> 1 + 4y/9 + 3x = 1 + 4y/24 => 9 + 3x = 24

=> 3x = 15

=>   x = 15 : 3

=>   x = 5

Answer 3

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