Tuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
\(\frac{1}{2}x\frac{1}{4}x^2\frac{x^3}{8}2y4y^28y^3\)
Giúp mik với!
\(\frac{1}{2}x\frac{1}{4}x^2\frac{x^3}{8}2y4y^28y^3\)
Thu gọn các đơn thức sau:
a) 1\(\frac{1}{4}\)x2y \(\left(\frac{-5}{6}xy\right)^0\)\(\left(-2\frac{1}{3}xy\right)\)
b) \(\frac{1}{2}x\frac{1}{4}x^2\frac{x^3}{8}2y4y^28y^3\)
c) \(\left(2\frac{1}{3}x^2y^3\right)^{10}\left(\frac{3}{7}x^5y^4\right)^{10}\)
d) \(\left(-\frac{a}{2}\right)^33xy\left(4a^2x^3\right)\left(4\frac{1}{3}ay^2\right)\)
Thu gọn các đơn thức sau rồi cho biết hệ số, phần biến, bậc của mỗi đơn thức:
a) \(\frac{1}{2}x\frac{1}{4}x^2^{ }\frac{x^3}{8}2y4y^28y^3\)
b)\(\left(2\frac{1}{3}x^2y^3\right)^{10}\left(\frac{3}{7}x^5y^4\right)^{10}\)
c)\(\left(-\frac{2}{3}a^2b\right)^3ba^2\left[-\frac{9}{4}\left(ab^2\right)^3\right]\left(\frac{a^3b}{2}\right)^2\)
d)\(\left(-\frac{1}{2}a\frac{4}{3}a^26a\right)^3.3^3\left(-b^2\right)\frac{1}{6}b8^3\)
e)\(\left(-\frac{a}{2}\right)^33xy\left(4a^2x^3\right)\left(4\frac{1}{3}ay^2\right)\) (a là hằng số khác 0)
tim x
a)\(2\frac{3}{4}x-1\frac{5}{8}x=1\)
b)\(2\frac{3}{4}x-1\frac{5}{8}x=1\)
c)\(\frac{3}{2}x-\frac{2}{5}=\frac{1}{3}x-\frac{1}{4}\)
d)\(2x-\frac{1}{4}=\frac{5}{6}-\frac{1}{2}x\)
e)\(\frac{-5}{6}+3x=\frac{2}{3}-\frac{1}{2}x\)
f)\(\frac{5}{2}x-\frac{3}{2}=x+\frac{29}{10}\)
g)\(\frac{2}{3}+\frac{7}{3}x=\frac{5}{4}x+\frac{1}{6}\)
h)\(\frac{1}{3}.x+\frac{2}{5}\left(x-1\right)=0\)
giup mk nha moi nguoi
\(\frac{2}{x-1.x-3}+\frac{5}{x-3.x-8}+\frac{12}{x-8.x-20}-\frac{1}{x-20}=\frac{-3}{4}\)
tìm x
Tìm x:
a, \(\left(\frac{x}{3}-\frac{2}{5}\right):\frac{-2}{5}+\frac{1}{2}x=\frac{-3}{4}\)
b. \(\left(\frac{-1}{8}x-\frac{3}{4}\right)-\frac{-8}{5}=\frac{5}{3}-x\)
c. \(\left(x-\frac{1}{3}\right)^{x+1}=\left(x-\frac{1}{3}\right)^x\)
d. \(\frac{x+2}{3}+\frac{2x-1}{4}\)
e. \(\left(\frac{3}{2}-x\right)^4=64^2\)
f. \(\left(5-\frac{x}{2}\right)^3-\frac{1}{27}=0\)
Nhờ các bạn giúp mik tí nha!
Tìm x biết
a) x+2x+3x+4x+...+100x=-213
b)\(\frac{1}{2}x-\frac{1}{3}=\frac{1}{4}x-\frac{1}{6}\)
c)3(x-2)+2(x-1)=10
d)\(\frac{x+1}{3}=\frac{x-2}{4}\)
e)\(\frac{x-6}{7}+\frac{x-7}{8}+\frac{x-8}{9}=\frac{x-9}{10}+\frac{x-10}{11}+\frac{x-11}{12}\)
f)\(\frac{x+32}{11}+\frac{x+23}{12}=\frac{x+38}{13}+\frac{x+27}{14}\)
a.\(\frac{x-6}{7}+\frac{x-7}{8}+\frac{x-8}{9}=\frac{x-9}{10}+\frac{x-10}{11}+_{\frac{x-11}{12}}\)
b.\(\frac{x-1}{2020}+\frac{x-2}{2019}-\frac{x-3}{2018}=\frac{x-4}{2017}\)
c.\(\left(\frac{3}{4}x+3\right)-\left(\frac{2}{3}x-4\right)-\left(\frac{1}{6}x+1\right)=\left(\frac{1}{3}x+4\right)-\left(\frac{1}{3}x-3\right)\)
giúp mk vs mk đg cần gấp
Thank you
