\(\frac{1}{2}+\frac{1}{5}=\frac{5}{10}+\frac{2}{10}=\frac{7}{10}\)
Ủng hộ nhé!
\(\frac{1}{2}\)+\(\frac{1}{5}\)=\(\frac{5}{10}\)+\(\frac{2}{10}\)=\(\frac{7}{10}\)
\(\frac{1}{2}-\frac{1}{3}-\frac{2}{3}+\frac{1}{4}+\frac{2}{4}+\frac{3}{4}-\frac{1}{5}-\frac{2}{5}-\frac{3}{5}-\frac{4}{5}+...+\frac{1}{10}+\frac{2}{10}+\frac{3}{10}+...+\frac{9}{10}\)\(+\)\(\frac{9}{10}\)
a) \(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}\) b) \(\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}+\frac{1}{243}+\frac{1}{729}\)
c) \(\frac{1}{5}+\frac{1}{10}+\frac{1}{20}+\frac{1}{40}+...............+\frac{1}{1280}\) d) \(\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{96}+\frac{2}{192}\)
e) \(1+\frac{5}{4}+\frac{5}{8}+\frac{5}{16}+\frac{5}{32}+\frac{5}{64}\) f) \(\frac{3}{2}+\frac{3}{8}+\frac{3}{32}+\frac{3}{128}+\frac{3}{512}\)
g) \(3+\frac{3}{5}+\frac{3}{25}+\frac{3}{125}+\frac{3}{625}\)
\(\frac{1}{1×2}+\frac{1}{2×3}\: +\frac{1}{3×4}\: +\frac{1}{4×5}+\frac{1}{5×6}\: +\frac{1}{6×7}+\frac{1}{7×8}+\frac{1}{8×9}\: =?\)
\(A=\)\(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}\)
\(B=\frac{2}{5}.\frac{15}{4}:\frac{5}{16}+\frac{1}{2}\)
Tính bằng cáh thuân tiện nhất
1- (\(1-\left(\frac{1}{2}x\frac{3}{5}+\frac{1}{5}x\frac{1}{2}+\frac{2}{10}x\frac{1}{2}+\frac{1}{2}\right)\)
\(\frac{1}{2}\times\frac{1}{5}+\frac{1}{5}\times\frac{1}{8}+\frac{1}{8}\times\frac{1}{11}+\frac{1}{11}\times\frac{1}{14}=?\)
\(\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{?}{?}=5\)
Bài 1 : tính theo cách hợp lý nhất
\(\frac{6}{11}+\frac{1}{3}+\frac{5}{11}\)
Bài 2 : Tính bằng cách nhanh nhất
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}\)
Bài 3 : Tính nhanh
a,\(\frac{3}{2}\times\frac{4}{5}\times\frac{2}{3}\)
b,\(\frac{6}{7}\times\subset\frac{5}{3}\times\frac{7}{6}\supset\)
Bài 4 : Tính nhanh
a,\(\frac{2}{5}\times\frac{1}{4}+\frac{3}{4}\times\frac{2}{5}\)
b,\(\frac{6}{11}\div\frac{2}{3}+\frac{5}{11}\div\frac{2}{3}\)
Dãy phân số nào được viết theo thứ tự từ bé đến lớn là :
A. \(\frac{1}{2},\frac{2}{5},\frac{2}{7}\) B. \(\frac{2}{7},\frac{2}{5},\frac{1}{2}\) C. \(\frac{2}{5},\frac{2}{7},\frac{2}{5}\) C. \(\frac{1}{2},\frac{2}{7},\frac{1}{7}\)
\(\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\right)-5\frac{5}{6}+\left(-\frac{35}{30.7}\right)=?\)