Đặt \(A=\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{97}}\)
\(2A=1+\frac{1}{2}+...+\frac{1}{2^{96}}\)
\(2A-A=\left(1+\frac{1}{2}+...+\frac{1}{2^{96}}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{97}}\right)\)
\(\Rightarrow A=1-\frac{1}{2^{97}}\)
Ủng hộ mk nha !!! ^_^