Đề bài là gì vậy bạn ??? Tính hay tìm x ?
\(\frac{0,\left(3\right)+0,\left(384615\right)+\frac{3}{13}x}{0,0\left(3\right)+13}\)
\(=\frac{\frac{1}{3}+\frac{5}{13}+\frac{3}{13}x}{\frac{1}{30}+13}=\frac{\frac{1}{3}+\frac{5+3x}{13}}{\frac{391}{30}}=\frac{\frac{13+3\left(5+3x\right)}{39}}{\frac{391}{30}}\)
\(=\frac{\frac{13+15+9x}{39}}{\frac{391}{90}}=\frac{\frac{28+9x}{39}}{\frac{391}{90}}=\frac{28+9x}{39}\cdot\frac{90}{391}\)
P/S : Sai đề trầm trọng
P/S : Tìm x vậy kết quả nó bao nhiêu mới tìm được chớ ?
Đề còn thiếu không vậy?
\(\frac{50}{85}\)
\(\frac{0,\left(3\right)+0,\left(384615\right)+\frac{3}{13}x}{0,0\left(3\right)+13}=\frac{50}{85}\)
=> \(\frac{\frac{1}{3}+\frac{5}{13}+\frac{3}{13}x}{\frac{1}{30}+13}=\frac{50}{85}\)
=> \(\frac{1}{3}+\frac{5}{13}+\frac{3}{13}x=\frac{50}{85}\cdot\left(\frac{1}{30}+13\right)\)
=> \(\frac{1}{3}+\frac{5}{13}+\frac{3}{13}x=\frac{50}{85}\cdot\frac{391}{30}=\frac{23}{3}\)
=> \(\frac{28}{39}+\frac{3}{13}x=\frac{23}{3}\)
=> \(\frac{3}{13}x=\frac{23}{3}-\frac{28}{39}=\frac{271}{39}\)
=> \(x=\frac{271}{39}:\frac{3}{13}=\frac{271}{39}\cdot\frac{13}{3}=\frac{271}{9}\)