\(\Delta_fH^o_{298}\left[CO_2\right]=-94,05\cdot4,184=-393,5052kJ\cdot mol^{-1}\\ \Delta_fH^o_{298}\left[CO\right]=\dfrac{-393,5052\cdot2-\left(-135,28\cdot4,184\right)}{2}=-110,5kJ\cdot mol^{-1}\)
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