\(a,PTHH:C+O_2\rightarrow CO_2\)
Ta có :
\(n_C=\frac{7,2}{12}=0,6\left(mol\right)\)
Theo phương trình : \(n_{O2}=n_C=0,2\left(mol\right)\)
\(\rightarrow V_{O2}=0,6.22,4=13,44\left(l\right)\)
\(b,PTHH:2KClO_3\rightarrow2KCl+3O_2\)
Ta có :\(n_{KClO_3}=\frac{2}{3}n_{O2}=0,4\left(mol\right)\)
\(\rightarrow m_{KClO_3}=0,4.\left(39+35,5+16.3\right)=49\left(g\right)\)
Trong không khí chứa 20% O2
\(\rightarrow V_{kk}=5V.O_2=5.13,44=67,2\left(l\right)\)