\(m_P=6,2\left(g\right)\Rightarrow n_P=\frac{6,2}{31}=0,2\left(mol\right)\)
\(PTHH:4P+5O_2\rightarrow2P_2O_5\)
\(\Rightarrow n_{P2O5}=\frac{1}{2}n_P=\frac{1}{2}.0,2=0,1\left(mol\right)\)
\(\Rightarrow m_{P2O5}=0,1.142=14,2\left(g\right)\)
Ta có :
\(n_{O2}=\frac{5}{4}n_P=\frac{5}{4}.0,2=0,25\left(mol\right)\)
\(\Rightarrow V_{O2}=0,25.22,4=5,6\left(l\right)\)
\(PTHH:4P+5O_2\underrightarrow{t^0}2P_2O_5\)
\(---4---5--2\left(mol\right)\)
Theo PTHH ta có:
\(\Rightarrow n_P=\frac{6,2}{31}=0,2\left(mol\right)\)
\(\Rightarrow n_{P_2O_5}=0,1\left(mol\right)\)
\(\Rightarrow n_{O_2}=0,25\left(mol\right)\)
\(\Rightarrow V_{O_2}=0,25.22,4=5,6l\)
\(\Rightarrow m_{P_2O_5}=0,1.142=14,2g\)