\(n_{C_2H_5OH}=\dfrac{13,8}{46}=0,3mol\)
\(C_2H_5OH+3O_2\rightarrow2CO_2+3H_2O\)
0,3 0,9 0,6 ( mol )
\(V_{CO_2}=0,6.22,4=13,44l\)
\(V_{kk}=\left(0,9.22,4\right).5=100,8l\)
C2H5OH+3O2-to>2CO2+3H2O
0,3------------0,9-----------0,6
n C2H5OH=0,3 mol
=>VCO2=0,6.22,4=13,44l
=>VO2=0,9.22,4.5=100,8l
\(n_{C_2H_5OH}=\dfrac{13,8}{46}=0,3mol\)
\(C_2H_5OH+3O_2\underrightarrow{t^o}2CO_2+3H_2O\)
0,3 0,9 0,6
\(V_{CO_2}=0,6\cdot22,4=13,44l\)
\(V_{O_2}=0,9\cdot22,4=20,16l\)
\(V_{kk}=5V_{O_2}=5\cdot20,16=100,8l\)
a, \(n_{C_2H_6O}=\dfrac{13,8}{46}=0,3\left(mol\right)\)
C2H6O + 3O2 ----to----> 2CO2 + 3H2O
0,3 0,9 0,6
\(V_{CO_2}=0,6.22,4=13,44\left(l\right)\)
a, \(V_{O_2}=0,9.22,4=20,16\left(l\right)\)
\(V_{kk}=20,16.5=100,8\left(l\right)\)
\(n_{C2H6O}=\dfrac{13,8}{46}=0,3\left(mol\right)\)
\(pthh:C_2H_6O+3O_2-t^o->2CO_2+3H_2O\)
0,3 0,9 0,6
=> \(V_{CO_2}=0,6.22,4=13,44\left(l\right)\)
=> \(V_{O_2}=0,9.22,4=20,169L\)
=> \(V_{KK}=V_{O_2}:20\%=0,9:20\%=4,5L\)
PTHH : \(C_2H_6O+3O_2\left(t^o\right)->2CO_2+3H_2O\) (1)
a) \(n_{C_2H_6O}=\dfrac{m}{M}=\dfrac{13,8}{46}=0,3\left(mol\right)\)
Từ (1) -> \(n_{CO_2}=2n_{C_2H_6O}=0,6\left(mol\right)\)
=> \(V_{CO_2\left(đktc\right)}=n.22,4=0,6.22,4=13,44\left(l\right)\)
b) Từ (1) -> \(n_{O_2}=3n_{C_2H_6O}=0,9\left(mol\right)\)
-> \(V_{kk\left(đktc\right)}=\dfrac{n_{O_2}.22,4}{20\%}=\dfrac{0,9.22,4}{20\%}=100,8\left(l\right)\)
C2H5OH+3O2-to>2CO2+3H2O
0,3------------0,9-----------0,6
n C2H5OH=0,3 mol
=>VCO2=0,6.22,4=13,44l
=>VO2=0,9.22,4.5=100,8l