\(\dfrac{x+9}{x+4}-\dfrac{5}{x-4}=\dfrac{-20}{x^2-16}\)ĐKXĐ:x khác +-4
=>\(\dfrac{\left(x+9\right).\left(x-4\right)}{\left(x+4\right)\left(x-4\right)}-\dfrac{5.\left(x+4\right)}{\left(x+4\right).\left(x-4\right)}=\dfrac{-20}{\left(x+4\right).\left(x-4\right)}\)
=> khử mẫu:
=>(x+9).(x-4)-5.(x+4)=-20
=>x2-4x+9x-36-5x-20=-20
=>x2-56=-20
=>x2=62
=>x=6