Question

\(\dfrac{x}{7}\)=\(\dfrac{x+16}{35}\)     

\(\dfrac{x-2}{2}\)=\(\dfrac{2}{x-2}\) 

\(\dfrac{x-1}{5}\)=\(\dfrac{x+3}{6}\)

TÌM X

Answer 1

a) \(\dfrac{x}{7}=\dfrac{x+16}{35}< =>x.35=\left(x+16\right).7\)

\(< =>35x=7x+112\)

\(< =>35x-7x=112=>28x=112< =>x=4\)

b) \(\dfrac{x-2}{2}=\dfrac{2}{x-2},,=>\left(x-2\right)\left(x-2\right)=4\)

\(=>\left[{}\begin{matrix}x-2=2\\x-2=-2\end{matrix}\right.=>\left[{}\begin{matrix}x=4\\x=0\end{matrix}\right.\)

c) \(\dfrac{x-1}{5}=\dfrac{x+3}{6}=>\left(x-1\right).6=\left(x+3\right).5\)

\(=>6x-6=5x+15\)

=> \(6x-5x=15+6=>x=21\)