Question

\(\dfrac{x}{5}=\dfrac{y}{3}\)và\(x^2-y^2=4\)

Answer 1

\(\dfrac{x}{5}=\dfrac{y}{3}\\ \rightarrow\dfrac{x^2}{25}=\dfrac{y^2}{9}\\ \rightarrow\dfrac{x^2}{25}=\dfrac{y^2}{9}=\dfrac{x^2-y^2}{25-9}=\dfrac{4}{16}=\dfrac{1}{4}\\ \rightarrow\left\{{}\begin{matrix}\left[{}\begin{matrix}x=\dfrac{5}{2}\\x=-\dfrac{5}{2}\end{matrix}\right.\\\left[{}\begin{matrix}y=\dfrac{3}{2}\\y=-\dfrac{3}{2}\end{matrix}\right.\end{matrix}\right.\)