MT

\(\dfrac{x+5}{2022}+\dfrac{x+4}{2023}+\dfrac{x+3}{2024}=-3\)

NT
22 tháng 6 2022 lúc 21:07

\(\dfrac{x+5}{2022}+\dfrac{x+4}{2023}+\dfrac{x+3}{2024}=-3\)

\(\Rightarrow\dfrac{x+5}{2022}+1+\dfrac{x+4}{2023}+1+\dfrac{x+3}{2024}+1=0\)

\(\Rightarrow\dfrac{x+5+2022}{2022}+\dfrac{x+4+2023}{2023}+\dfrac{x+3+2024}{2024}=0\)

\(\Rightarrow\dfrac{x+2027}{2022}+\dfrac{x+2027}{2023}+\dfrac{x+2027}{2024}=0\)

\(\Rightarrow\left(x+2027\right)\left(\dfrac{1}{2022}+\dfrac{1}{2023}+\dfrac{1}{2024}\right)=0\)

\(\Rightarrow x+2027=0\)

\(\Rightarrow x=-2027\)

 

 

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H24
22 tháng 6 2022 lúc 21:08

`[x+5]/2022+[x+4]/2023+[x+3]/2024=-3`

`=>[x+5]/2022+1+[x+4]/2023+1+[x+3]/2024+1=-3+1+1+1`

`=>[x+5+2022]/2022+[x+4+2023]/2023+[x+3+2024]/2024=0`

`=>[x+2027]/2022+[x+2027]/2023+[x+2027]/2024=0`

`=>(x+2027)(1/2022+1/2023+1/2024)=0`

  Mà `1/2022+1/2023+1/2024 \ne 0`

 `=>x+2027=0`

 `=>x=-2027`

Vậy `x=-2027`

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