Question

\(\dfrac{x+4}{5}-x+4=\dfrac{x}{3}-\dfrac{x-2}{2}\)

Answer 1

<=> \(\dfrac{6.\left(x+4\right)}{6.5}-\dfrac{30\left(x+4\right)}{30}=\dfrac{10x}{30}-\dfrac{15\left(x-2\right)}{15.2}\)

<=> \(\dfrac{6x+24}{30}-\dfrac{30x+120}{30}=\dfrac{10x}{30}-\dfrac{15x-30}{30}\)

<=> \(\dfrac{6x+24}{30}-\dfrac{30x+120}{30}-\dfrac{10x}{30}+\dfrac{15x-30}{30}=0\)

<=> \(6x+24-30x-120-10x+15x-30=0\)

<=> \(-19x-126=0\)

<=> \(-19x=126\)

<=> \(x=\dfrac{126}{-19}=-\dfrac{126}{19}\)