Question

\(\dfrac{\left(\sqrt{x+3}-x\right)\left(\sqrt{x+3}+2\right)}{x-1}\)

Rút gọn

Answer 1

sửa đề \(\dfrac{\left(\sqrt{x+3}-2\right)\left(\sqrt{x+3}+2\right)}{x-1}=\dfrac{x+3-4}{x-1}=\dfrac{x-1}{x-1}=1\)

đk x khác 1