\(\dfrac{3}{4}+\dfrac{5}{8}=\dfrac{6}{8}+\dfrac{5}{8}=\dfrac{11}{8}\)
\(6-\dfrac{3}{7}=\dfrac{6}{1}-\dfrac{3}{7}=\dfrac{42}{7}-\dfrac{3}{7}=\dfrac{39}{7}\)
\(\dfrac{3}{4}\times\dfrac{2}{5}=\dfrac{3\times2}{4\times5}=\dfrac{6}{20}=\dfrac{3}{10}\)
\(\dfrac{3}{7}:\dfrac{4}{9}=\dfrac{3}{7}\times\dfrac{9}{4}=\dfrac{27}{28}\)