Question

\(\dfrac{26}{19}.\dfrac{4}{25}+\dfrac{7}{5}.\dfrac{3}{5}-\dfrac{4}{25}.\dfrac{7}{19}\)

Answer 1

\(\dfrac{26}{19}.\dfrac{4}{25}+\dfrac{7}{5}.\dfrac{3}{5}-\dfrac{4}{25}.\dfrac{7}{19}=\dfrac{104}{475}+\dfrac{7}{5}.\dfrac{3}{5}-\dfrac{4}{25}.\dfrac{7}{19}=\dfrac{104}{475}+\dfrac{21}{25}-\dfrac{4}{25}.\dfrac{7}{19}=\dfrac{503}{475}-\dfrac{4}{25}.\dfrac{7}{19}=\dfrac{503}{475}-\dfrac{28}{475}=\dfrac{475}{475}=1\)

Answer 2

\(\dfrac{26}{19}\cdot\dfrac{4}{25}+\dfrac{7}{5}\cdot\dfrac{3}{5}-\dfrac{4}{25}\cdot\dfrac{7}{19}=\dfrac{4}{25}\cdot\left(\dfrac{26}{19}-\dfrac{7}{19}\right)+\dfrac{7}{5}\cdot\dfrac{3}{5}=\dfrac{4}{25}\cdot1+\dfrac{21}{25}=\dfrac{4}{25}+\dfrac{21}{25}=\dfrac{25}{25}=1\)