Question

\(\dfrac{1}{3}-\dfrac{1}{3}:\left(-\dfrac{2}{3}\right)^2+\left(-3\right)^3.\left(7\dfrac{7}{9}-9\dfrac{2}{3}\right)\)

Answer 1

Lời giải:

$=\frac{1}{3}-\frac{1}{3}: \frac{4}{9}+(-27).\frac{-17}{9}$

$=\frac{1}{3}-\frac{1}{3}.\frac{9}{4}+51$

$=\frac{1}{3}-\frac{3}{4}+51=\frac{607}{12}$