\(\dfrac{111\times118-33}{112\times115+185}\)
= \(\dfrac{111\times\left(115+3\right)-33}{\left(111+1\right)\times115+185}\)
= \(\dfrac{111\times115+111\times3-33}{111\times115+115\times1+185}\)
= \(\dfrac{111\times115+333-33}{111\times115+115+185}\)
= \(\dfrac{111\times115+300}{111\times115+300}\)
= 1
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