H24

\(\dfrac{10}{x+3}-\dfrac{8x-36}{x^2-9}\)

AT
4 tháng 12 2022 lúc 18:43

\(ĐK:x\ne\pm3\\ \dfrac{10}{x+3}-\dfrac{8x-36}{x^2-9}\\ =\dfrac{10}{x+3}-\dfrac{8x-36}{\left(x-3\right)\left(x+3\right)}\\ =\dfrac{10\left(x-3\right)}{\left(x-3\right)\left(x+3\right)}-\dfrac{8x-36}{\left(x-3\right)\left(x+3\right)}\\ =\dfrac{10x-30-8x+36}{\left(x-3\right)\left(x+3\right)}\\ =\dfrac{2x+6}{\left(x-3\right)\left(x+3\right)}\\ =\dfrac{2\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}\\ =\dfrac{2}{x-3}\)

Bình luận (0)
PU
4 tháng 12 2022 lúc 18:47

\(=\dfrac{10}{x+3}-\dfrac{8x-36}{\left(x-3\right)\left(x+3\right)}=\dfrac{10\left(x-3\right)-8x+36}{\left(x-3\right)\left(x+3\right)}=\dfrac{10x-30-8x+36}{\left(x-3\right)\left(x+3\right)}=\dfrac{2x+6}{\left(x-3\right)\left(x+3\right)}=\dfrac{2\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}=\dfrac{2}{x-3}\)

Bình luận (0)
NV
4 tháng 12 2022 lúc 20:16

\(\dfrac{8x-36}{x^2-9}=\dfrac{8x-36}{\left(x-3\right)\left(x+3\right)}\)

\(MTC:\left(x+3\right)\left(x-3\right)\)

\(\dfrac{10.\left(x-3\right)}{\left(x+3\right)\left(x-3\right)}=\dfrac{10x-30}{\left(x+3\right)\left(x-3\right)}\)

\(\dfrac{8x-36.\left(1\right)}{\left(x+3\right)\left(x-3\right)}=\dfrac{8x-36}{\left(x+3\right)\left(x-3\right)}\)

\(\dfrac{10x-30}{\left(x+3\right)\left(x-3\right)}-\dfrac{8x-36}{\left(x+3\right)\left(x-3\right)}\)

\(=\dfrac{\left(10x-30\right)-\left(8x-36\right)}{\left(x+3\right)\left(x-3\right)}\)

\(=\dfrac{10x-30-8x+36}{\left(x+3\right)\left(x-3\right)}\)

\(=\dfrac{2x+6}{\left(x+3\right)\left(x-3\right)}=\dfrac{2\left(x+3\right)}{\left(x+3\right)\left(x-3\right)}=\dfrac{2}{x-3}\)

 

Bình luận (0)

Các câu hỏi tương tự
HH
Xem chi tiết
H24
Xem chi tiết
HP
Xem chi tiết
ZH
Xem chi tiết
CD
Xem chi tiết
TH
Xem chi tiết
TN
Xem chi tiết
NL
Xem chi tiết
NT
Xem chi tiết
H24
Xem chi tiết