Question

\(\dfrac{1}{-12}+\dfrac{3}{4}+\dfrac{-1}{12}-\dfrac{1}{3}\)

Answer 1

\(\dfrac{1}{-12}+\dfrac{3}{4}+\dfrac{-1}{12}-\dfrac{1}{3}=\dfrac{-1}{12}+\dfrac{3}{4}+\dfrac{-1}{12}-\dfrac{1}{3}=\dfrac{-1}{12}+\dfrac{9}{12}+\dfrac{-1}{12}-\dfrac{4}{12}=\dfrac{\text{3}}{12}=\dfrac{1}{4}\)

Answer 2

\(=\dfrac{1}{-12}+\dfrac{9}{12}+\dfrac{-1}{12}-\dfrac{4}{12}=\dfrac{3}{12}=\dfrac{1}{4}\)