Điều kiện: \(x\ne0\)
\(-\dfrac{5}{12}:x=\dfrac{20}{-16}\\ \Rightarrow-\dfrac{5}{12}.\dfrac{1}{x}=-\dfrac{5}{4}\\ \Rightarrow-\dfrac{5}{12x}=-\dfrac{5}{4}\\ \Rightarrow12x=-5:-\dfrac{5}{4}=-5.-\dfrac{4}{5}=\dfrac{20}{5}=4\\ \Rightarrow x=\dfrac{4}{12}=\dfrac{1}{3}\left(thỏa.mãn\right)\)
Vậy x = \(\dfrac{1}{3}\)
Đúng 1
Bình luận (0)