Question

\(\dfrac{-15}{4}\) x 3\(\dfrac{1}{3}\)- \(1\dfrac{3}{4}\)+ \(\dfrac{7}{8}\)

Answer 1

\(\dfrac{-15}{4}\times3\dfrac{1}{3}-1\dfrac{3}{4}+\dfrac{7}{8}\\ =\dfrac{-15}{4}\times\dfrac{10}{3}-\dfrac{7}{4}+\dfrac{7}{8}\\ =-\dfrac{5}{2}\times5-\dfrac{7}{4}+\dfrac{7}{8}\\ =\dfrac{-25}{2}-\dfrac{7}{4}+\dfrac{7}{8}\\ =\dfrac{-100}{8}-\dfrac{14}{8}+\dfrac{7}{8}\\ =\dfrac{-107}{8}\)

Answer 2

\(\dfrac{-15}{4}\)x3\(\dfrac{1}{3}\)-1\(\dfrac{3}{4}\)+\(\dfrac{7}{8}\)

= \(\dfrac{-15}{4}\)x\(\dfrac{10}{3}\)-\(\dfrac{7}{4}\)+\(\dfrac{7}{8}\)

= \(\dfrac{-25}{2}\)-\(\dfrac{7}{4}\)+\(\dfrac{7}{8}\)

= \(\dfrac{-57}{4}\)+\(\dfrac{7}{8}\)

= \(\dfrac{-107}{8}\)

Answer 3

`-15/4 xx 3 1/3 - 1 3/4 + 7/8`

`=-15/4xx10/3-7/4+7/8`

`=-150/12-14/8+7/8`

`=-25/2-14/8+7/8`

`=-100/8-14/8+7/8`

`=-114/8+7/8`

`=-107/8`