Ta có : \(V_{O_2}=224m^3=224000l\)
\(\Rightarrow n_{O_2}=\frac{224000}{22,4}=1000\left(mol\right)\)
PTHH : \(2H_2O\rightarrow2H_2\uparrow+O_2\uparrow\)
Theo phương trình : \(n_{H_2O}=2n_{O_2}\Rightarrow n_{H_2O}=2000\left(mol\right)\)
\(\Rightarrow m_{H_2O}=2000.18=36000\left(kg\right)\)