⇔ đầu =x2-2x+2x-4
\(\dfrac{\left(x-1\right)\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}\)=x2+2x-x-2
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Bình luận (1)
⇔ đầu =x2-2x+2x-4
\(\dfrac{\left(x-1\right)\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}\)=x2+2x-x-2