Lời giải:
$3(|x|-\frac{4}{5})+0,2=0,5$
$3(|x|-\frac{4}{5})=0,3$
$|x|-\frac{4}{5}=0,3:3=0,1$
$|x|=0,1+\frac{4}{5}=0,9$
$\Rightarrow x=\pm 0,9$
b. \(\dfrac{8^2.6^3}{9^2.16^2}\)
c. \(\dfrac{\left(0,15\right)^4}{\left(0,5\right)^5}\)
d. \(\left(\dfrac{3}{4}\right)^3\). \(\left(\dfrac{16}{9}\right)^3\)
a)\(0,5+\dfrac{1}{3}+0,4+\dfrac{5}{7}-\dfrac{1}{6}-\dfrac{4}{35}\)
b)\(\left(3-\dfrac{1}{4}+\dfrac{2}{3}\right)-\left(5+\dfrac{1}{3}-\dfrac{6}{5}\right)-\left(-6-\dfrac{7}{4}+\dfrac{3}{2}\right)\)
c)\(\dfrac{1}{3}-\dfrac{3}{4}-\left(-\dfrac{3}{5}\right)+\dfrac{1}{64}-\dfrac{2}{9}-\dfrac{1}{36}+\dfrac{1}{15}\)
Mn giúp em ạ!
TÍNH:
a, A = \(\dfrac{2}{3}+\dfrac{3}{4}.\left(\dfrac{-4}{9}\right)\)
b, B = \(2\dfrac{3}{11}.1\dfrac{1}{12}.\left(-2,2\right)\)
c, C = \(\left(\dfrac{3}{4}-0,2\right).\left(0,4-\dfrac{4}{5}\right)\)
tìm x:
\(a,5^x.\left(5^2\right)^3=625\)
\(b,\left(\dfrac{12}{15}\right)^x=\left(\dfrac{5}{4}\right)^{-2}-\left(\dfrac{-3}{5}\right)^4\)
\(c,\left(\dfrac{-3}{4}\right)^{3x-1}=\dfrac{256}{81}\)
\(d,172x^2-7^9:98^3=2^{-3}\)
tìm x biết:
a) \(5^x.\left(5^3\right)^2=625\)
b)\(\left(\dfrac{12}{15}\right)^x=\left(\dfrac{5}{3}\right)^{-5}-\left(-\dfrac{3}{5}\right)^4\)
c)\(\left(-\dfrac{3}{4}\right)^{3x-1}=\dfrac{256}{81}\)
d)\(172x^2-7^9:98^3=2^{-3}\)
Tính:
a) [\(\left(-2,7\right)^4\)]5 - [(-2,7)2 ] 10
b) (-0,5)5 : (-0,5)3 - \(\left(\dfrac{17}{2}\right)^7\) : \(\left(\dfrac{17}{2}\right)^6\)
c) (814 : 412) : (166 : 82)
Câu 13. (0,5 điểm): Tính giá trị $\left(2+\dfrac{1}{3}-0,4\right)-\left(7-\dfrac{3}{5}-\dfrac{4}{3}\right)-\left(\dfrac{1}{5}+\dfrac{5}{3}-4\right)$.
\(5\dfrac{5}{27}+\dfrac{7}{23}-0,5.\dfrac{5}{27}+\dfrac{16}{23}=\)
\(45\dfrac{1}{6}:\left(\dfrac{-4}{5}\right)-35\dfrac{1}{6}:\left(\dfrac{-4}{5}\right)=\)
\(25.\left(\dfrac{-1}{5}\right)^3+\dfrac{1}{5}-2.\left(\dfrac{-1}{2}\right)^2-\dfrac{1}{2}=\)
\(\left(3,1-2,5\right)-\left(-2,5-3,1\right)=\)
\(\dfrac{3}{8}.\dfrac{7}{5}-\dfrac{7}{5}.\dfrac{1}{8}+\dfrac{13}{20}=\)
CẦN GẤP NGAY VÀ LUÔN :)))))
Tính bằng cách hợp lí giá trị của biểu thức.
A = \(\left(3-\dfrac{1}{4} +\dfrac{3}{2}\right)\)- \(\left(5+\dfrac{1}{3}-\dfrac{5}{6}\right)\)-\(\left(6-\dfrac{7}{4}+\dfrac{3}{2}\right)\)
B =\(0,5+\dfrac{1}{3}+0,4+\dfrac{5}{7}+\dfrac{1}{6}-\dfrac{4}{35}+\dfrac{1}{41}\)
