Question

Cứu

Answer 1

\(1,\\ ĐKXĐ:6-3x>0\Leftrightarrow-3x>-6\Leftrightarrow x< 2\)

\(2,A=\sqrt{5-2\sqrt{6}}-\sqrt{\left(\sqrt{2}-\sqrt{3}\right)^2}\\ A=\sqrt{\left(\sqrt{3}-\sqrt{2}\right)^2}-\left|\sqrt{2}-\sqrt{3}\right|\\ A=\left|\sqrt{3}-\sqrt{2}\right|-\left(\sqrt{3}-\sqrt{2}\right)\\ A=\sqrt{3}-\sqrt{2}-\sqrt{3}+\sqrt{2}=0\)