Question

Cu --> CuCl2 --> Cu(OH)2 --> CuO --> CuCl2

Answer 1

\(\left(1\right)Cu+Cl_2\overset{t^o}{--->}CuCl_2\)

\(\left(2\right)CuCl_2+2NaOH--->Cu\left(OH\right)_2+2NaCl\)

\(\left(3\right)Cu\left(OH\right)_2\overset{t^o}{--->}CuO+H_2O\)

\(\left(4\right)CuO+2HCl--->CuCl_2+H_2O\)

Answer 2

Cu+Cl₂-to>CuCl₂

CuCl₂+2NaOH->2NaCl+Cu(OH)2

Cu(oH)₂->CuO+H₂O

CuO+2HCl->CuCl₂+H2O