Question

cot (\(\dfrac{x}{4}\)+ 20\(^o\)) = -\(\sqrt{3}\) 

Answer 1

\(cot\left(\dfrac{x}{4}+20^o\right)=-\sqrt{3}\)

\(\Leftrightarrow cot\left(\dfrac{x}{4}+20^o\right)=cot\left(-30^o\right)\)

\(\Leftrightarrow\dfrac{x}{4}+20^o=-30^o+k.180^o\)

\(\Leftrightarrow x=-200^o+k.720^o\)