cos6x . cos2x + \(\dfrac{1}{2}\) = 0
⇔ 2cos6x . cos2x + 1 = 0
⇔ cos8x + cos4x + 1 = 0
⇔ 2cos24x + cos4x = 0
⇔ \(\left[{}\begin{matrix}cos4x=0\\cos4x=-\dfrac{1}{2}\end{matrix}\right.\)
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