Các câu hỏi tương tự
CMR \(\forall n\in\)N* ta có
\(\left(1-\frac{1}{2}\right)+\left(\frac{1}{3}-\frac{1}{4}\right)+\left(\frac{1}{5}-\frac{1}{6}\right)+...+\left(\frac{1}{2n-1}-\frac{1}{2n}\right)=\frac{1}{n+1}+\frac{1}{n+2}+...+\frac{1}{2n}\)
\(CMR:\frac{1}{4^2}+\frac{1}{6^2}+\frac{1}{8^2}+...+\frac{1}{\left(2n\right)^2}< \frac{1}{4}\)
KN
16 tháng 3 2019 lúc 10:08
CMR: \(\frac{1}{4^2}+\frac{1}{6^2}+\frac{1}{8^2}+...+\frac{1}{\left(2n\right)^2}< \frac{1}{4}\)
CMR: \(\frac{1}{4^2}+\frac{1}{6^2}+\frac{1}{8^2}+...+\frac{1}{\left(2n\right)^2}<\frac{1}{4}\)
CMR: \(\frac{1}{4^2}+\frac{1}{6^2}+\frac{1}{8^2}+\frac{1}{10^2}+...+\frac{1}{\left(2n\right)^2}<\frac{1}{4}\)
CMR: \(N=\frac{1}{4^2}+\frac{1}{6^2}+\frac{1}{8^2}+...+\frac{1}{\left(2n\right)^2}< \frac{1}{4}\)(n thuộc N , n lớn hơn bằng 2)
Câu 1 Tính giá trị biểu thức:a) A 2+5+8+11+...+2012b) Bleft(1-frac{1}{2}right).left(1-frac{1}{3}right).left(1-frac{1}{4}right).....left(1-frac{1}{2011}right).left(1-frac{1}{2012}right)Câu 2a) Tìm x,y nguyên biết : 2x.(3y-2) + (3y-2) -55b) CMR:frac{1}{4^2}+frac{1}{6^2}+frac{1}{8^2}+...+frac{1}{left(2nright)^2} frac{1}{4}
Đọc tiếp
Câu 1 Tính giá trị biểu thức:
a) A= \(2+5+8+11+...+2012\)
b) B=\(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right).....\left(1-\frac{1}{2011}\right).\left(1-\frac{1}{2012}\right)\)
Câu 2
a) Tìm x,y nguyên biết : 2x.(3y-2) + (3y-2) = -55
b) CMR:
\(\frac{1}{4^2}+\frac{1}{6^2}+\frac{1}{8^2}+...+\frac{1}{\left(2n\right)^2}< \frac{1}{4}\)
a) CMR: \(\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+...+\frac{1}{n^2}< \frac{3}{4}\)
b) CMR: \(\frac{1}{3^2}+\frac{1}{5^2}+\frac{1}{7^2}+...+\frac{1}{\left(2n+1\right)^2}< \frac{1}{4}\)
Chứng minh :\(\frac{1}{4^2}+\frac{1}{6^2}+\frac{1}{8^2}+...+\frac{1}{\left(2n\right)^2}< \frac{1}{4}\)