Tuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
CMR:\(\frac{1}{41}+\frac{1}{42}+\frac{1}{43}+...+\frac{1}{80}>\frac{7}{12}\)
Giúp mik vs mọi người ơi!
Chứng tỏ rằng: \(\frac{1}{41}+\frac{1}{42}+\frac{1}{43}+...+\frac{1}{79}+\frac{1}{80}>\frac{7}{12}\)
Cm: \(\frac{1}{41}+\frac{1}{42}+\frac{1}{43}+...+\frac{1}{79}+\frac{1}{80}>\frac{7}{12}\)
Chứng tỏ rằng :\(y=\frac{1}{41}+\frac{1}{42}+\frac{1}{43}+...+\frac{1}{79}+\frac{1}{80}>\frac{7}{12}\)
CMR:
\(\frac{1}{41}\)+ \(\frac{1}{42}\)+\(\frac{1}{43}\)+...+\(\frac{1}{79}\)+\(\frac{1}{80}\)>\(\frac{7}{12}\)
Chứng minh rằng :\(\frac{1}{41}+\frac{1}{42}+\frac{1}{43}+...+\frac{1}{79}+\frac{1}{80}>\frac{7}{12}\)
chứng tỏ rằng :
\(\frac{1}{41}+\frac{1}{42}+\frac{1}{43}+...+\frac{1}{79}+\frac{1}{80}>\frac{7}{12}\)
GIÚP TỚ VỚI !!!!!!!!!!
chứng minh
\(\frac{7}{12}< \frac{1}{41}+\frac{1}{42}+\frac{1}{43}+...+\frac{1}{80}< 1\)
CM::
\(\frac{1}{41}+\frac{1}{42}+\frac{1}{43}+\frac{1}{44}+............+\frac{1}{79}+\frac{1}{80}>\frac{7}{12}\)
