Gọi UWCLN(5n+3,3n+2) = d
Ta có: \(\left\{{}\begin{matrix}5n+3⋮d\\3n+2⋮d\end{matrix}\right.\)\(\Rightarrow\left\{{}\begin{matrix}3\left(5n+3\right)⋮d\\5\left(3n+2\right)⋮d\end{matrix}\right.\)\(\Rightarrow\left\{{}\begin{matrix}15n+9⋮d\\15n+10⋮d\end{matrix}\right.\)
\(\Rightarrow\left(15n+10\right)-\left(15n+9\right)⋮d\)
\(\Rightarrow1⋮d\)
\(\Rightarrow d=\pm1\)
=> đpcm
Đoạn đầu là ƯCLN(5n+3,3n+2)=d bạn nhé, bị lỗi mà mình không để ý