Ta có:
\(\left(3a+4b\right)⋮11\)
\(\Rightarrow4\left(3a+4b\right)⋮11\)
\(\Rightarrow\left(12a+16b\right)⋮11\)
\(\Rightarrow\left(\left(11a+11b\right)+\left(a+5b\right)\right)⋮11\)
\(\Rightarrow\left(a+5b\right)⋮11\)
3a+4b chia hết cho 11
=>12a+16b chia hết cho 11
(12a+16b) - (a+5b) = 11a+11b
11a+11b chia hết cho 11
12a+16b chia hết cho 11
=>a+5b chia hết cho 11