\(-x^2+4x-5=-\left(x^2-4x+5\right)=-\left(x^2-4x-4+1\right)=-\left(x^2-4x-4\right)-1=-\left(x-2\right)^2-1\le-1< 0\)
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\(-x^2+4x-5=-\left(x^2-4x+5\right)=-\left(x^2-4x-4+1\right)=-\left(x^2-4x-4\right)-1=-\left(x-2\right)^2-1\le-1< 0\)