Question

CM đẳng thức:

\(\dfrac{x^2y\:+\:2xY\:^2+y^3}{2x^2+xY\:-y^2}\:=\:\dfrac{xY\:+\:y^2}{2x-y}\)

Answer 1

\(=\dfrac{y\left(x^2+2xy+y^2\right)}{2x^2+2xy-xy-y^2}\)

\(=\dfrac{y\left(x+y\right)^2}{\left(x+y\right)\left(2x-y\right)}=\dfrac{y\left(x+y\right)}{2x-y}\)

\(=\dfrac{xy+y^2}{2x-y}\)