Tuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
Ta thấy :
\(\frac{1}{2^2}< \frac{1}{1\cdot2}\)
\(\frac{1}{3^2}< \frac{1}{2\cdot3}\)
..............
\(\frac{1}{8^2}< \frac{1}{7\cdot8}\)
=> B
\(=\frac{1}{2^2}+\frac{1}{3^2}+...+\frac{1}{8^2}< \frac{1}{1\cdot2}+\frac{1}{2\cdot3}+...+\frac{1}{7\cdot8}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{7}-\frac{1}{8}=1-\frac{1}{8}\)
\(< 1\)
Vậy
Bài 1:Chứng tỏ rằng:B=\(\dfrac{1}{2^2}\)+\(\dfrac{1}{3^2}\)+\(\dfrac{1}{4^2}\)+\(\dfrac{1}{5^2}\)+\(\dfrac{1}{6^2}\)+\(\dfrac{1}{7^2}\)\(\dfrac{1}{8^2}\)<1
Bài 2:Chứng tỏ rằng:E=\(\dfrac{3}{4}\)+\(\dfrac{8}{9}\)+\(\dfrac{15}{16}\)+...+\(\dfrac{2499}{2500}\)<1
Bài 3:Chứng tỏ rằng:1<\(\dfrac{2011}{2020^2+1}\)+\(\dfrac{2021}{2020^2+2}\)+\(\dfrac{2021}{2020^3+3}\)+...+\(\dfrac{2021}{2020^3+2020}\)< 2
chứng tỏ rằng:B=1/2^2 + 1/3^2 + 1/4^2 + 1/5^2 + 1/6^2 + 1/7^2 + 1/8^2 < 1
Chứng tỏ rằng :B=1/2^2+1/3^2+1/4^2+1/5^2+1/6^2+1/7^2+1/8^2<1
chứng tỏ rằng B= 1/2 ^ 2+1/3 ^ 2 + 1/4 ^ 2+1/5 ^ 2 +1/6 ^ 2+ 1/7 ^ 2+1/8 ^ 2< 1
chứng tỏ rằng B= 1/2^2 + 1/3^2 +1/4^2+1/5^2+1/6^2+1/7^2+1/8^2 <1
Chứng tỏ rằng: B= 1/2 mũ 2 +1/3 mũ 2 +1/4 mũ 2 + 1/5 mũ 2 + 1/6 mũ 2+ 1/7 mũ 2 + 1/8 mũ 2 <1.
Chứng tỏ rằng : B = 1/2 mũ 2 + 1/3 mũ 2 + 1/4 mũ 2 + 1/ 5 mũ 2 + 1/6 mũ 2 +1/7 mũ 2 + 1/8 mũ 2 < 1
Chứng tỏ rằng : B =1/2 mũ 2 + 1/3 mũ 2 + 1/4 mũ 2 + 1/5 mũ 2 + 1/6 mũ 2 + 1/7 mũ 2 +1/8 mũ 2 <1
chứng tỏ rằng
b= 1/2^2+1/3^2+1/4^2+1/5^2+1/6^2+1/7^2+1/8^2<1
b tính nhanh
A= 1+1/2(1+2) +1/3(1+2+3)+1/4(1+2+3+4)+...+ 1/16(1+2+3+...+16)