Ta có:
\(VP=\frac{1}{n}-\frac{1}{n+1}=\frac{n+1}{n\left(n+1\right)}-\frac{n}{n\left(n+1\right)}=\frac{n+1-n}{n\left(n+1\right)}\)
\(=\frac{n-n+1}{n\left(n+1\right)}=\frac{0+1}{n\left(n+1\right)}=\frac{1}{n\left(n+1\right)}=VT\)
Vậy \(\frac{1}{n\left(n+1\right)}=\frac{1}{n}-\frac{1}{n+1}\) (Đpcm)