Chứng tỏ
a, 1/2-1/4+1/8-1/16+1/32-1/64<1/3
b, 1/3-2/3^2+3/3^3-4/3^4+...+99/3^99-100/3^100<3/16
c, 1/2.3/4.5/6...9999/10000<1/100
Chưng tỏ
a, S= 1/2^2+1/3^2+...+1/9^2
Chứng tỏ 2/5<S<8/9
b, 1/2-1/4+1/8-1/16+1/32-1/64<1/3
c, 1/3-2/3^2+3/3^3-4/3^4+...+99/3^99-100/3^100<3/16
\(\frac{1}{3}-\frac{2}{3^2}+\frac{3}{3^3}-\frac{4}{3^4}+...+\frac{99}{3^{99}}-\frac{100}{3^{100}}< \frac{3}{16}\)
Đề bài: Chứng tỏ rằng (trên)
Chứng tỏ rằng
[200-(3+2/3+2/4+2/5+...+2/100]:[1/2+2/3+3/4+...+99/100]=2
chứng tỏ rằng:1/2^2+1/3^2+1/4^2+...+1/99^2+1/100^2<3/4
Chứng mình `S<1/5`.
`S=1/3 - 2/(3^2) + 3/(3^3) - 4/(3^4) + ... +99/(3^99) - 100/(3^100)`
Chứng tỏ rằng: 1/2*3+1/3*4+1/4*5+....+1/99*100<1/2
Chứng minh rằng 1/3-3/2^2+3/3^3-4/3^4+...+99/3^99-100/3^100
Chứng tỏ giúp mình với !
\(\frac{200-\left(3+\frac{2}{3}+\frac{2}{4}+\frac{2}{5}+...+\frac{99}{100}\right)}{\frac{1}{2}+\frac{2}{3}+\frac{3}{4}+...+\frac{99}{100}}=2\)
chứng minh: 1/3-2/3^2+3/3^3-4/3^4+...+99/3^99-100/3^100<3/16
