(10^2 + 5.10^2 + 5^3):(6^3 + 3. 6^2 + 3^3) = (100 + 500 + 125):(216 + 108 + 27) = 725 : 351 = ... chet cha lon de :D
(10^2 + 5.10^2 + 5^3):(6^3 + 3. 6^2 + 3^3) = (100 + 500 + 125):(216 + 108 + 27) = 725 : 351 = ... chet cha lon de :D
B1: Tính
a) (1/4)44. (1/2)12
b) \(\frac{3^{17}.81^{11}}{27^{10}.9^{15}}
\)
c)\(\frac{14^{16}.21^{32}.35^{48}}{10^{16}.15^{32}.7^{96}}\)
d)\(\frac{\left(5^4-5^3\right)^3}{125^4}\)
e)\(\frac{10^3+5.10^2+5^3}{6^3+3.6^2+3^3}\)
tính
\(\frac{10^3+5.10^2+5^3}{6^3+3.6^2+3^3}\)
Thuc hien phep tinh;
a/ \(\frac{5}{15}+\frac{14}{15}-\frac{12}{9}+\frac{2}{7}+\frac{11}{25}\)
b/ \(4.\frac{-1^3}{2}+\frac{1}{2}\)
c/ \(\frac{10^3+5.10^2+5^3}{6^3+3.6^2+3^3}\)
d/ \(\frac{2^8.9^2}{6^4.8^2}\)
e/(\(9\frac{3}{4}:5,2+3,4.2\frac{7}{34}\)):(-1\(\frac{9}{16}\))
f/\(\frac{\frac{2^3}{3}.\frac{-3^2}{4}.\left(-1\right)^5}{\frac{2^2}{5}.\frac{-5^3}{6}}\)
\(\frac{15^5.10^5}{6^6.25^6}\)
2.\(\frac{\left(5^4.5^3\right)^3}{125^4}\)
Bài 1 : Tính :
a)\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right)\times230\frac{1}{5}+46\frac{3}{4}}{\left(1\frac{3}{10}+\frac{10}{3}\right)\div\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
b) \(\frac{2^{12}\times3^5-4^6\times9^2}{\left(2^4\times3\right)^6+8^4\times3^5}-\frac{5^{10}\times7^3-25^5\times49^2}{\left(125\times7\right)^3+5^9\times14^3}\)
c)P=\(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+....+\frac{1}{2016}}{\frac{2015}{1}+\frac{2014}{2}+\frac{2013}{3}+....+\frac{1}{2015}}\)
10 mũ 3 + 5.10 mũ 2+5 mũ 3 trên
6 mũ 3+3.6 mũ 2 +3 mũ 3
Rút gọn
b) \(\frac{36^7}{2^{15}27^5}\)
h) \(\frac{2^{18}.9^4}{6^6.8^4}\)
o) \(\frac{3^3+3.6^2+6^3}{13}\)
Thanks <3
Bài 1: Tính
\(\left(-\frac{10}{3}\right)^3\cdot\left(-\frac{6}{5}\right)^4\)
Bài 2: Rút gọn
a) \(2:\left(\frac{1}{2}-\frac{2}{3}\right)^3\)
b) \(\frac{6^3+3.6^2+3^3}{-13}\)
\(\frac{0.6^5}{0.2^6}\)
\(\frac{2^7.9^3}{6^5.8^2}\)
\(\frac{6^3}{-13}+3.6^2+3^3\)