\(A=16^5+2^{15}=\left(2^4\right)^5+2^{15}\)
\(=2^{20}+2^{15}\)
\(=2^{15}.\left(2^5+1\right)\)
\(=2^{15}.\left(32+1\right)\)
\(=2^{15}.33\)chia hết cho 33.
A = 165 + 215
A = (24)5 + 215
A = 220 + 215
A = 215.(25 + 1)
A = 215.33 chia hết cho 33
=> A chia hết cho 33 ( đpcm)
Ủng hộ mk nha ☆_★^_-
Ta có :
\(A=16^5+2^{15}=\left(2^4\right)^5+2^{15}\)
\(=2^{20}+2^{15}\)
\(=2^{15}.\left(2^5+1\right)\)
\(=2^{15}.\left(32+1\right)\)
\(=2^{15}.33\)chia hết ch 33 (ĐPCM)
Uả 16^5 = 4^20 mà
Cho mik hỏi là 2¹⁵.(2⁵+1) Ở đâu v ạk