2+2^2+2^3+...+2^60
=(2+2^2+2^30)+...+(2^58+2^59+2^60)
=2*(1+2+2^2)+...+2^58*(1+2+2^2)
=2*7+...+2^58*7
=(2+...+2^58)*7
Suy ra ĐPCM
A=2+22+23+...+260
=(2+22+23)+...+(258+259+260)
=2.(1+2+22)+...+258.(1+2+22)
=2.7+...+258.7
=7.(2+...+258) chia hết cho 7