Hãy chứng tỏ rằng : 100-[1+1/2+1/3+...+1/100] = 1/2+2/3+3/4+...+99/100
Mình cần gấp
tính nhanh (2/3+3/4+5/6+...+99/100).(1/2+2/3+3/4+...+98/99)-(1/2+1/3+...+99/100).(2/3+2/4+...+98/99)
(2+4+6+...+100) - (1+3+5+...+99) = ?
1 x 2 + 2 x 3 + 3 x 4 + ... + 99 x 100 = ?
3 x 4 + 4 x 5 + 5 x 6 + ... + 149 x 150 = ?
1 + (1 + 2) + ( 1 + 2 + 3) + (1 + 2 + 3 + 4) + ....... + (1 + 2 + 3 + ... + 99)
----------------------------------------------------------------------------------------------------------- ( gạch ngang phân số )
1 x 99 + 2.98 + 3.97 + ...... + 99 x 1
r)18*123+9*4567*2+5310*6 / (2+4+6+...+20+22)+48
d)71+65*4=y+140/y+260
b11:Hãy chứng tỏ rằng :
100 - {1+1/2+1/3+...+1/100} = 1/2+2/3+3/4+...+99/100
1+1/2*2+1/3*3+1/4*4+.....+1/99*99+1/100*100
Biết 1 + 2 + 3 + 4 + ... + 99 + 100 = 5050, hãy tính 1 + 2 + 3 + 4 + ... + 99 - 100.
Tính A:B
a)A=98+1/2+1/3+1/4+...+1/99
B=2/3+4/3+5/4+...+100/99
b)A=2018+1/2+1/3+1/4+...+1/2019
B=3/2+4/3+3/4+...+2020/2019
c)A=99/1+98/2+97/3+...+2/98+1/99
B=1/2+1/3+1/4+...+1/100
Giải đầy đủ
1*2*3+2*3*4+3*4*5+....+97*98*99+98*99*100 = ?
1 + 2 + 3 + ... + 99 + 100
2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18
1 + 2 + 3 + 4 + ... + 200
