Question

chứng minh rằng (2²⁰²⁰ - 2²⁰¹⁷) :^{. 7}

 

 

 

Answer 1

2²⁰²⁰ - 2²⁰¹⁷

= 2³ . 2²⁰¹⁷ - 2²⁰¹⁷

= 2²⁰¹⁷ . ( 2³ - 1 )

= 2²⁰¹⁷ . 7 \(⋮\)7

Vậy \(\left(2^{2020}-2^{2017}\right)⋮7\)\(\left(\text{đ}pcm\right)\)

Answer 2

\(2^{2020}-2^{2017}=2^{2017}\left(2^3-1\right)=2^{2017}.7⋮7\left(ddpcm\right)\)

Answer 3

\(\left(2^{2020}-2^{2017}\right)⋮7\)

=\(2^{2017}.2^3-2^{2017}\)

=\(2^{2017}.\left(2^3+1\right)\)

=\(2^{2017}.7⋮7\)

Vậy \(\left(2^{2020}-2^{2017}\right)⋮7\)

Hok tốt

Answer 4

\(\text{Chứng minh rằng : }(2^{2020}-2^{2017})⋮7\)

\(\text{Ta có :}2^{2020}-2^{2017}=2^3\cdot2^{2017}-2^{2017}\)

\(=2^{2017}(2^3-1)\)

\(=2^{2017}\cdot8-1⋮7\)

\(=2^{2017}\cdot7⋮7(đ\text{pcm})\)